⚙️ Oil Burner Wizard

Power • flow • nozzle • efficiency • now also: kW from annual consumption & hours
🧪 Oil type

📆 0. Burner power from annual consumption

🔥 Burner thermal power 35.4 kW

⛽ Average flow: 3.57 l/h | 3.00 kg/h

(at η=100% burner power; actual boiler output = burner power × efficiency)

Example: 1400 h/year, 5000 liters EL → avg. flow = 5000/1400 = 3.57 l/h. With 11.8 kWh/kg, ρ=0.84 → 3.57 l/h = 3.00 kg/h → 3.00 × 11.8 = 35.4 kW burner (at 100% efficiency).
Our calculation takes oil type (EL or S) into account.

1. Boiler power → flow

3.20 kg/h

3.80 l/h

2. Nozzle size (US-gph)

🧩 0.75 US-gph

3. Measuring time

6.0 min

4. Flue gas η

📈 92.5 %

loss 7.5%


📏 Suction line indication (EL)

Min. diameter 10 mm

Advised 12 mm

📋 Oil Burner Installation Report

PDF preview
🔥 Burner power from annual consumption
Operating hours / year1400 h
Annual consumption5000 liter
Oil typeLight fuel oil EL
Average flow3.57 l/h | 3.00 kg/h
Burner thermal power (100% η)35.4 kW
⚙️ Boiler & nozzle
Boiler power Q34.0 kW
Efficiency η90.0 %
Resulting flow3.20 kg/h | 3.80 l/h
Nozzle flow (input)3.80 l/h
Pressure / ref pressure12.5 bar / 7.0 bar
Nozzle size (US-gph)0.75 gph
⏱️ Measuring & flue gas
Flow for time test20.0 l/h
Volume collected2.0 liter
Measuring time6.0 min
CO₂ / O₂CO₂ 13.5 %
Flue gas temp190 °C
Intake air temp20 °C
Delta T170 K
Calculated efficiency η92.5 %
Flue gas loss7.5 %
📏 Suction line (EL)
Length / height diff10 m / 2 m
Min. diameter10 mm
Advised diameter12 mm
📌 Calculation summary: Burner power from annual consumption = (liters/year / hours) * density * calorific value. Nozzle size (US-gph) = flow(l/h) / (3.78 * √(p/pref)). Flue gas efficiency uses Siegert formula.
Report generated · Oil Burner Wizard · values based on current inputs