⚙️ Oil Burner Wizard

Power • flow • nozzle • efficiency • now also: kW from annual consumption & hours
🧪 Oil type

📆 0. Burner power from annual consumption

🔥 Burner thermal power 35.4 kW

⛽ Average flow: 3.57 l/h | 3.00 kg/h

(at η=100% burner power; actual boiler output = burner power × efficiency)

Example: 1400 h/year, 5000 liters EL → avg. flow = 5000/1400 = 3.57 l/h. With 11.8 kWh/kg, ρ=0.84 → 3.57 l/h = 3.00 kg/h → 3.00 × 11.8 = 35.4 kW burner (at 100% efficiency).
Our calculation takes oil type (EL or S) into account.

1. Boiler power → flow

⛽ 3.20 kg/h

⛽ 3.80 l/h

2. Nozzle size (US-gph)

🧩 0.75 US-gph

3. Measuring time

⏳ 6.0 min

4. Flue gas η

📈 92.5 %

loss 7.5%

📏 Suction line indication (EL)

Min. diameter 10 mm

Advised 12 mm

💡 Burner power from annual consumption: flow (l/h) = annual consumption (l) / hours → kg/h = l/h * ρ → power (kW) = kg/h * calorific value (kWh/kg).
Oil type EL: 11.8 kWh/kg, 0.84 kg/l | S: 11.2 kWh/kg, 0.96 kg/l.